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OSV
OSV
added 2026/06/26 8:24 p.m.7 views

JLSEC-2026-646 When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption...

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that all image channels have the same pixel type and size, and that if there are four channels, the first four are "B", "G", "R" and "A". The channel parsing code can be found in decodeheader. The...

8.7CVSS6.6AI score0.00172EPSS
Exploits0References4
OSV
OSV
added 2026/06/26 8:24 p.m.4 views

JLSEC-2026-644 When decoding an OpenEXR file that uses DWAA or DWAB compression, the specified raw length of run...

When decoding an OpenEXR file that uses DWAA or DWAB compression, the specified raw length of run-length-encoded data is not checked when using it to calculate the output data. We read rlerawsize from the input file at 0, we decompress and decode into the buffer td-rlerawdata of size rlerawsize a...

6.9CVSS6.5AI score0.00161EPSS
Exploits0References4
AstraLinux
AstraLinux
added 2026/01/13 2:1 p.m.6 views

Astra Linux – Vulnerability in ffmpeg

When decoding an OpenEXR file that uses DWAA or DWAB compression, there is an implicit assumption that the height and width are divisible by 8. If the height or width of the image is not divisible by 8, the copy operation will loop at positions 0 and 1, continuing to write until a multiple of 8 i...

8.7CVSS6.6AI score0.00156EPSS
Exploits0References3
OSV
OSV
added 2025/10/06 8:15 a.m.2 views

DEBIAN-CVE-2025-59733

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that all image channels have the same pixel type and size, and that if there are four channels, the first four are "B", "G", "R" and "A". The channel parsing code can be found in decodeheader. The...

8.7CVSS5.9AI score0.00172EPSS
Exploits0References1
Debian CVE
Debian CVE
added 2025/10/06 8:9 a.m.4 views

CVE-2025-59732

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that the height and width are divisible by 8. If the height or width of the image is not divisible by 8, the copy loops at 0 and 1 will continue to write until the next multiple of 8. The buffer...

8.7CVSS5.9AI score0.00156EPSS
Exploits0
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