Astra Linux – Vulnerability in ffmpeg5

When decoding an OpenEXR file that uses DWAA or DWAB compression, there is an implicit assumption that the height and width are divisible by 8. If the height or width of the image is not divisible by 8, the copy operation will loop at positions 0 and 1, continuing to write until a multiple of 8 i...

OESA-2026-3286 ffmpeg security update

FFmpeg is a complete and free Internet live audio and video broadcasting solution for Linux/Unix. It also includes a digital VCR. It can encode in real time in many formats including MPEG1 audio and video, MPEG4, h263, ac3, asf, avi, real, mjpeg, and flash. Security Fixes: When decoding an OpenEX...

JLSEC-2026-644 When decoding an OpenEXR file that uses DWAA or DWAB compression, the specified raw length of...

When decoding an OpenEXR file that uses DWAA or DWAB compression, the specified raw length of run-length-encoded data is not checked when using it to calculate the output data. We read rlerawsize from the input file at 0, we decompress and decode into the buffer td-rlerawdata of size rlerawsize a...

JLSEC-2026-646 When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption...

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that all image channels have the same pixel type and size, and that if there are four channels, the first four are "B", "G", "R" and "A". The channel parsing code can be found in decodeheader. The...

DEBIAN-CVE-2025-59733

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that all image channels have the same pixel type and size, and that if there are four channels, the first four are "B", "G", "R" and "A". The channel parsing code can be found in decodeheader. The...

CVE-2025-59732

When decoding an OpenEXR file that uses DWAA or DWAB compression, there's an implicit assumption that the height and width are divisible by 8. If the height or width of the image is not divisible by 8, the copy loops at 0 and 1 will continue to write until the next multiple of 8. The buffer...